The All India Council for Technical Skill Development has launched the Aryabhatta National Maths Competition for the students of India. To help students who are enthusiastic about mathematics, the AICTSD has launched the Aryabhatta National Maths Competition 2024 for school students. This scholarship going to be a great chance for all the students who want to achieve technical skills and technical leadership at the academy institutional level in the country. A student who wants to apply for this scholarship cancel the application form by visiting the official website of AICTSD. This scholarship gives the chance to the student to test your knowledge in the subject of mathematics.
Importance of Aryabhatta National Maths Competition
The Aryabhatta National Maths Competition was launched by AICTSD. Under this scheme, the students will get a chance to identify and nurture their mathematical talent for the students of India. The Aryabhatta National Maths Competition provides a high-quality entrance exam for students and produces the best results year after year. All the students who clear the eligibility criteria and want to be a part of this competition can fill out the application form before 30th April 2024. This scholarship is a great opportunity for all the students who want to pursue higher education in mathematics without wearing about any financial hurdle
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Objective of Aryabhatta National Maths Competition
To motivate the financially unstable students, the organization has launched the Aryabhatta National Maths Competition. Under this scholarship, the student will be able to appear in the competitive examination without worrying about any financial hurdles. After appearing in the examination the student will be rewarded with the competition certificate. The certificate will help students to pursue higher education. They can use this certificate in their profession also. This scholarship will empower the students of India to continue their education in the mathematics field
Key Highlights of Aryabhatta National Maths Competition
| Name of the scholarship | Aryabhatta National Maths Competition |
| Launched by | AICTSD |
| Objective | Provide financial assistance |
| Beneficiaries | College and high school students |
| Official website | Aryabhatta Website |
Eligibility Criteria
- An applicant must be a permanent resident of India
- Students from any school or college are eligible.
- The student’s age must be from 10 to 24 years.
- Candidates who are studying in classes 4th to 12th are eligible
Benefits of Aryabhatta National Maths Competition
- The scholarship will allow students to pursue higher education in the mathematical field without worrying about any financial problems.
- With the help of this scheme, students will be able to check their potential in mathematics
- The student who wants to apply for competitive exams will be able to understand the competitive environment
- Five students at each level can collect their awards and certificates from their respective schools after the results
- The student who will get the certificate will get a huge value in academic and professional career
Required Documents
- Passport size photo
- Signature
- 10th certificate
- Admission slip
- Education certificate
- Income proof
- Other significant documents
Important Dates
| Activity | Dates |
| Last Date of Registration | 30th April 2024 |
| Online Exam Date | 21st May 2024 |
| Result Date | 10th June 2024 |
| Online Live Interview | 20th June 2024 |
| Final Result Date | 30th June 2024 |
Also Check: NRTS Scholarship Exam
Application fee
- The applicant needs to pay the application processing fee of INR 290 to be part of this competitive exam.
Syllabus
| Class 4 | Syllabus |
| Class 5 | Syllabus |
| Class 6 | Syllabus |
| Class 7 | Syllabus |
| Class 8 | Syllabus |
| Class 9 | Syllabus |
| Class 10 | Syllabus |
| Class 11 | Syllabus |
| Class 12 | Syllabus |
Reward Details
| 1st Prize | Students will be provided with prize money of INR 25,000Industrial Certified National Level AICTSD Certificate will be provided. Students will get a National Mathematics Scientist trophy for 3 months of free training & R&D on Robotics AutomationStudents will get INR 30,000 free of cost online live training. Candidates will get the National Mathematics Scientist ScholarshipStudents will get a level project competition organized by AICTSD. |
| 2nd Prize | Students will be provided with prize money of INR 50,000Industrial industrial-certified National Level AICTSD Certificate will be provided. Students will get a National Mathematics Scientist trophy for 6 months of free training & R&D on Robotics AutomationStudents will get INR 50,000 free of cost online live training. Candidates will get the National Mathematics Scientist ScholarshipStudents will get a level project competition organized by AICTSD. |
| 3rd Prize | The 4th runner will get prize money of INR 2000 for each of 250 candidates ranked from 4th to 53rd grade Students will be rewarded with industrial certified National level AICTSD. Candidates will get a chance in a National level project competition organized by the organization. The applicants will also get a national mathematic scientist scholarship |
| 4th Prize | Students will be provided with prize money of INR 1 lakhs Industrial–certified National Level AICTSD Certificate will be provided. Students will get a National Mathematics Scientist trophy 1 year of free training & R&D on Robotics AutomationStudents will get INR 1 lakh free of cost online live training. Candidates will get a National Mathematics Scientist ScholarshipStudents will get a level project competition organized by AICTSD. |
| 5th Prize | Students will be provided with prize money of INR 1 lakhs Industrial–certified National Level AICTSD Certificate will be provided. Students will get a National Mathematics Scientist trophy 1 year of free training & R&D on Robotics AutomationStudents will get INR 1 lakh free of cost online live training. Candidates will get National Mathematics Scientist ScholarshipStudents will get a level project competition organized by AICTSD. |
Selection Process
- The candidates will be selected based on clearance of eligibility criteria.
- The student must give the application registration number from today’s respective school before the last date
- The candidates must register themselves with the organization to appear in the examination
- The student must be studying in class 4th to 12th to be selected for the examination
Also Check: Pathani Samanta Mathematics Scholarship Test
Steps to Apply for Aryabhatta National Maths Competition 2023
Applicants need to follow the below-given steps to apply for the Competition:
- First of all, go to the Aryabhatta website of the AICTSD
- The homepage of the website will open on the screen.
- Click on the “Aryabhatta National Maths Competition ANMC Link 2024.
- Now, check your age group and register yourself
- Once you are successfully registering yourself, click on the Apply Now button
- An application form will open on the screen.
- Now, fill in the form with all the required details.
- After that proceed to the payment gateway.
- Pay the application fee of Rs 290 in online mode.
- Within 48 hours of completing the online application process, a confirmation email containing the hall ticket number will be issued to the registered e-mail address.
- Candidates will be banned from registering as soon as all seats are filled, regardless of the registration date. Every year, around two lakh students apply for this exam, however, AICTSD only accepts the first 10,000 applicants, with the other applications being rejected and their payments being reimbursed.
Contact Us
- Email Id: director@aictsd.com
- Toll-Free Number to Call – 7229861562
Aryabhatta National Maths Competition 2024 FAQs
The Aryabhatta National Maths Competition is a scheme that provides a competitive environment for students.
Applicants can apply under this scheme by visiting https://www.aictsd.com/anmc/
Candidates can contact us at 7229861562 and director@aictsd.com when face any issues while applying for this exam
The application fee to apply under this scheme is INR 290.